What is the derivative of f(x)=2x^2-12x+8 ?

The derivative of f(x)=2x^2-12x+8 is 4x-12

What is the first derivative of f(x)=2x^2-12x+8 ?

The first derivative of f(x)=2x^2-12x+8 is 4x-12

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derivative of

f (x) = 2 x^{2} - 12 x + 8

4 x - 12

Solution steps

\frac{d}{d x} (2 x^{2} - 12 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (12 x) + \frac{d}{d x} (8)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (8) = 0

= 4 x - 12 + 0

Simplify

= 4 x - 12

\frac{d}{d x} ((x^{2} + y^{2})^{3})

y = (1 + sin (7 t))^{- 6}

\frac{d y}{d t} = \frac{t e ^{t}}{y 9 + y ^{2}}

\frac{d}{d x} (y^{2} e^{x y - 3})

What is the derivative of f(x)=2x^2-12x+8 ?
The derivative of f(x)=2x^2-12x+8 is 4x-12
What is the first derivative of f(x)=2x^2-12x+8 ?
The first derivative of f(x)=2x^2-12x+8 is 4x-12