What is the derivative of x^3+2y ?

The derivative of x^3+2y is 3x^2+2(dy)/(dx)

What is the first derivative of x^3+2y ?

The first derivative of x^3+2y is 3x^2+2(dy)/(dx)

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\frac{d}{d x} (x^{3} + 2 y)

3 x^{2} + 2 \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{3} + 2 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 y)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 y) = 2 \frac{d y}{d x}

= 3 x^{2} + 2 \frac{d y}{d x}

x \to \infty lim (t^{x})

x \to 4 lim (x^{2} - 4 x)

x \to - 5 lim (\frac{x + 1}{x + 5})

f (y) = y

x \to \infty lim (\frac{9}{x})

What is the derivative of x^3+2y ?
The derivative of x^3+2y is 3x^2+2(dy)/(dx)
What is the first derivative of x^3+2y ?
The first derivative of x^3+2y is 3x^2+2(dy)/(dx)