What is the limit as x approaches 3+of sqrt(x^2-9) ?

The limit as x approaches 3+of sqrt(x^2-9) is 0

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limit as x approaches 3+of sqrt(x^2-9)

x \to 3 + lim (x^{2} - 9)

0

Solution steps

x \to 3 + lim (x^{2} - 9)

Plug in the value

x = 3

= 3^{2} - 9

Simplify

= 0

\frac{d}{d x} (\frac{x ^{2}}{x ^{4} + 16})

\frac{d}{d x} (\frac{x - 2}{x + 3})

f (x) = e^{6}

\frac{\partial}{\partial x} (ln ((x y)^{z}))

\frac{\partial}{\partial x} (x^{2} + w^{2})

What is the limit as x approaches 3+of sqrt(x^2-9) ?
The limit as x approaches 3+of sqrt(x^2-9) is 0