What is the sum from n=1 to infinity of 1/(n+1) ?

The sum from n=1 to infinity of 1/(n+1) is diverges

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sum from n=1 to infinity of 1/(n+1)

n = 1 \sum \infty \frac{1}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n + 1}

Apply Series Limit Comparison Test:

diverges

= diverges

\int \frac{( 2 x + 2 )}{( x ^{2} + 1 ) ( x - 1 ) ^{3}} d x

y = (arctan (2 x))^{2}

\frac{d}{d x} (arctan (x^{3}))

\frac{d}{d x} (arcsin (5 x^{2}))

\frac{\partial}{\partial x} (x^{2} y - 1)

What is the sum from n=1 to infinity of 1/(n+1) ?
The sum from n=1 to infinity of 1/(n+1) is diverges