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Popular >

y^'=(2y+1)cot(x)

Solution

y^{^{'}} = (2 y + 1) cot (x)

Solution

y = \frac{c _{1} sin ^{2} ( x )}{2} - \frac{1}{2}

Solution steps

y^{'} (x) = (2 y + 1) cot (x)

Solve separable ODE:

y = \frac{c _{1} sin ^{2} ( x )}{2} - \frac{1}{2}

y = \frac{c _{1} sin ^{2} ( x )}{2} - \frac{1}{2}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(2y+1)cot(x) ?
The solution for y^'=(2y+1)cot(x) is y=(c_{1}sin^2(x))/2-1/2