What is the integral of (5cos(x)-4,x) ?

The integral of (5cos(x)-4,x) is 5sin(x)-4,(x^2)/2+C

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integral of (5cos(x)-4,x)

\int (5 cos (x) - 4, x) d x

5 sin (x) - 4, \frac{x ^{2}}{2} + C

Solution steps

\int 5 cos (x) - 4, x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (x) d x - \int 4, x d x

\int 5 cos (x) d x = 5 sin (x)

\int 4, x d x = 4, \frac{x ^{2}}{2}

= 5 sin (x) - 4, \frac{x ^{2}}{2}

Add a constant to the solution

= 5 sin (x) - 4, \frac{x ^{2}}{2} + C

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What is the integral of (5cos(x)-4,x) ?
The integral of (5cos(x)-4,x) is 5sin(x)-4,(x^2)/2+C