What is the sum from n=1 to infinity of n^2(1/2)^n ?

The sum from n=1 to infinity of n^2(1/2)^n is converges

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sum from n=1 to infinity of n^2(1/2)^n

n = 1 \sum \infty n^{2} (\frac{1}{2})^{n}

converges

Solution steps

n = 1 \sum \infty n^{2} (\frac{1}{2})^{n}

Apply Series Ratio Test:

converges

= converges

(y^{2} - x y) d x + x^{2} d y = 0, μ = \frac{1}{x ^{2}}

(2.1) (1.6)

ln (\frac{x ^{2}}{3 x + 1})

(x + 1) y^{^{'}} = x + y

\int \frac{x}{9 + x ^{2}} d x

What is the sum from n=1 to infinity of n^2(1/2)^n ?
The sum from n=1 to infinity of n^2(1/2)^n is converges