What is the integral of 3x^2+6x+5 ?

The integral of 3x^2+6x+5 is x^3+3x^2+5x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3x^2+6x+5

\int 3 x^{2} + 6 x + 5 d x

x^{3} + 3 x^{2} + 5 x + C

Solution steps

\int 3 x^{2} + 6 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int 6 x d x + \int 5 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 5 d x = 5 x

= x^{3} + 3 x^{2} + 5 x

Add a constant to the solution

= x^{3} + 3 x^{2} + 5 x + C

\frac{\partial}{\partial y} (z^{3} - x^{2} y)

(x cos (x))^{^{'}}

f (x) = x^{3} (3 - x^{2})

f (x) = \frac{x}{x ^{2} - 7}

\int \frac{2 x}{( x - 3 ) ^{2}} d x