What is the solution for (dy)/(dx)=((y-1))/(x^2) ?

The solution for (dy)/(dx)=((y-1))/(x^2) is y=e^{-1/x+c_{1}}+1

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(dy)/(dx)=((y-1))/(x^2)

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2}}

y = e^{- \frac{1}{x} + c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2}}

Solve separable ODE:

y = e^{- \frac{1}{x} + c_{1}} + 1

y = e^{- \frac{1}{x} + c_{1}} + 1

6 cos (2 x)

\int_{1}^{t} \frac{21}{x ^{3}} d x

9 x^{- 4}

\int \frac{1 + x}{1 - 2 x - x ^{2}} d x

690 (1 - (\frac{x}{345})^{2})

What is the solution for (dy)/(dx)=((y-1))/(x^2) ?
The solution for (dy)/(dx)=((y-1))/(x^2) is y=e^{-1/x+c_{1}}+1