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Popular >

f^'(x)=xe^{-x^2}

Solution

f^{^{'}} (x) = x e^{- x^{2}}

Solution

f (x) = - \frac{1}{2} e^{- x^{2}} + c_{1}

Solution steps

f^{'} (x) = x e^{- x^{2}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x e^{- x^{2}} d x

\int x e^{- x^{2}} d x = - \frac{1}{2} e^{- x^{2}} + c_{1}

f (x) = - \frac{1}{2} e^{- x^{2}} + c_{1}

Popular Examples

laplacetransform e^{-5t}*e^{25t}cos(20t)laplace transform

e^{- 5 t} \cdot e^{25 t} cos (20 t)

integral of (1-t^2)^3

\int (1 - t^{2})^{3} d t

derivative of y=x^{-3}+5x^{-2}derivative of

y = x^{- 3} + 5 x^{- 2}

y^'=(x-y)/(x+y),y(0)=1

y^{^{'}} = \frac{x - y}{x + y}, y (0) = 1

derivative of (sin(x-x)/(x^2))

\frac{d}{d x} (\frac{sin ( x ) - x}{x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=xe^{-x^2} ?
The solution for f^'(x)=xe^{-x^2} is f(x)=-1/2 e^{-x^2}+c_{1}