What is the integral of x^2+3e^x+C ?

The integral of x^2+3e^x+C is (x^3)/3+3e^x+Cx+C

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integral of x^2+3e^x+C

\int x^{2} + 3 e^{x} + C d x

\frac{x ^{3}}{3} + 3 e^{x} + C x + C

Solution steps

\int x^{2} + 3 e^{x} + C d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 3 e^{x} d x + \int C d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 3 e^{x} d x = 3 e^{x}

\int C d x = C x

= \frac{x ^{3}}{3} + 3 e^{x} + C x

Add a constant to the solution

= \frac{x ^{3}}{3} + 3 e^{x} + C x + C

\frac{1}{1 - \frac{1}{1 - x}}

\frac{\partial}{\partial y} (tan (5 + 2 x^{2} y^{4} z^{2}))

\frac{\partial}{\partial y} (e^{y} x)

\int cos (θ) sin^{3} (θ) d θ

9 y^{^{''}} + 32 y = 0, y^{^{'}} (0) = 9, y (0) = 5

What is the integral of x^2+3e^x+C ?
The integral of x^2+3e^x+C is (x^3)/3+3e^x+Cx+C