What is the limit as x approaches 0+of (36-4x^2)/x ?

The limit as x approaches 0+of (36-4x^2)/x is infinity

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limit as x approaches 0+of (36-4x^2)/x

x \to 0 + lim (\frac{36 - 4 x ^{2}}{x})

\infty

Solution steps

x \to 0 + lim (\frac{36 - 4 x ^{2}}{x})

Expand

\frac{36 - 4 x ^{2}}{x} : \frac{36}{x} - 4 x

= x \to 0 + lim (\frac{36}{x} - 4 x)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (\frac{36}{x}) - x \to 0 + lim (4 x)

x \to 0 + lim (\frac{36}{x}) = \infty

x \to 0 + lim (4 x) = 0

= \infty - 0

Apply Infinity Property:

\infty - c = \infty

= \infty

\int_{0}^{\infty} \frac{1}{2 + e ^{x}} d x

\int \frac{1}{8 - 5 x} d x

+ o f + \frac{x - 4}{x + 4}

\int \frac{x ^{5} - 3125}{x - 5} d x

f (x) = 3 x^{2} + 12 x - 36

What is the limit as x approaches 0+of (36-4x^2)/x ?
The limit as x approaches 0+of (36-4x^2)/x is infinity