What is the tangent of f(x)=(5x)/(x-2),(3,15) ?

The tangent of f(x)=(5x)/(x-2),(3,15) is y=-10x+45

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tangent of f(x)=(5x)/(x-2),(3,15)

tangent of

f (x) = \frac{5 x}{x - 2}, (3, 15)

y = - 10 x + 45

Solution steps

Find the slope of

f (x) = \frac{5 x}{x - 2} : \frac{df ( x )}{d x} = - \frac{10}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 10

Find the line with slope m=

- 10

and passing through

(3, 15) : y = - 10 x + 45

y = - 10 x + 45

- y^{^{''}} + 36 y = 0

\frac{d}{d x} (x^{\frac{7}{2}})

6 y

y^{^{'}} = k (1 - y)^{2}

\int (\frac{1}{x ^{2}}) d x

What is the tangent of f(x)=(5x)/(x-2),(3,15) ?
The tangent of f(x)=(5x)/(x-2),(3,15) is y=-10x+45