What is (\partial)/(\partial x)(e^{-2t}cos(x)) ?

The answer to (\partial)/(\partial x)(e^{-2t}cos(x)) is -e^{-2t}sin(x)

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(\partial)/(\partial x)(e^{-2t}cos(x))

\frac{\partial}{\partial x} (e^{- 2 t} cos (x))

- e^{- 2 t} sin (x)

Solution steps

\frac{\partial}{\partial x} (e^{- 2 t} cos (x))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 2 t} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= e^{- 2 t} (- sin (x))

Simplify

= - e^{- 2 t} sin (x)

\frac{d}{d x} (A (e^{x} + e^{xx}))

y^{^{''}} + 13 y^{^{'}} + 30 y = 0, y (0) = 1, y^{^{'}} (0) = 0

x \to \infty lim (\frac{5}{x} - 2)

\int (3 x + 5)^{3} d x

f (x) = x^{4} sin (4 x)

What is (\partial)/(\partial x)(e^{-2t}cos(x)) ?
The answer to (\partial)/(\partial x)(e^{-2t}cos(x)) is -e^{-2t}sin(x)