What is the limit as m approaches 0 of m/(m^2+4m) ?

The limit as m approaches 0 of m/(m^2+4m) is 1/4

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limit as m approaches 0 of m/(m^2+4m)

m \to 0 lim (\frac{m}{m ^{2} + 4 m})

\frac{1}{4}

Decimal

0.25

Solution steps

m \to 0 lim (\frac{m}{m ^{2} + 4 m})

Simplify

\frac{m}{m ^{2} + 4 m} : \frac{1}{m + 4}

= m \to 0 lim (\frac{1}{m + 4})

Plug in the value

m = 0

= \frac{1}{0 + 4}

Simplify

= \frac{1}{4}

\int e^{4 x - 3} d x

\int \frac{( x - 1 )}{( x - 2 ) ( x - 3 )} d x

x \to 2 lim (∣ x ∣)

x \to 0 lim (x + 5)

\frac{d}{d x} (ln (3 x^{5} + 2))

What is the limit as m approaches 0 of m/(m^2+4m) ?
The limit as m approaches 0 of m/(m^2+4m) is 1/4