What is the tangent of f(x)=12sqrt(x),(4,24) ?

The tangent of f(x)=12sqrt(x),(4,24) is y=3x+12

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tangent of f(x)=12sqrt(x),(4,24)

tangent of

f (x) = 12 x, (4, 24)

y = 3 x + 12

Solution steps

Find the slope of

f (x) = 12 x : \frac{df ( x )}{d x} = \frac{6}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(4, 24) : y = 3 x + 12

y = 3 x + 12

y^{^{''}} + 6 y^{^{'}} + 8 y = e^{2 x}

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = - 1, y^{^{'}} (0) = 4

\int e^{2 - 5 x} d x

x \to 2 + lim (\frac{1}{x ^{2} - 5 x + 6})

2 y^{^{''}} + (a + 1) y = 0

What is the tangent of f(x)=12sqrt(x),(4,24) ?
The tangent of f(x)=12sqrt(x),(4,24) is y=3x+12