What is the derivative of g(x)=x^2(1-7x) ?

The derivative of g(x)=x^2(1-7x) is 2x-21x^2

What is the first derivative of g(x)=x^2(1-7x) ?

The first derivative of g(x)=x^2(1-7x) is 2x-21x^2

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derivative of

g (x) = x^{2} (1 - 7 x)

2 x - 21 x^{2}

Solution steps

\frac{d}{d x} (x^{2} (1 - 7 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 1 - 7 x

= \frac{d}{d x} (x^{2}) (1 - 7 x) + \frac{d}{d x} (1 - 7 x) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 - 7 x) = - 7

= 2 x (1 - 7 x) + (- 7) x^{2}

Simplify

2 x (1 - 7 x) + (- 7) x^{2} : 2 x - 21 x^{2}

= 2 x - 21 x^{2}

\frac{d}{d x} ((\frac{x + 7}{x - 7})^{5})

\frac{d}{d x} ((ln (9))^{x})

\int (ln (y)) d y

\int \frac{( 5 x + 7 )}{( x ^{2} + 4 x + 4 )} d x

(x + 3)

What is the derivative of g(x)=x^2(1-7x) ?
The derivative of g(x)=x^2(1-7x) is 2x-21x^2
What is the first derivative of g(x)=x^2(1-7x) ?
The first derivative of g(x)=x^2(1-7x) is 2x-21x^2