What is (\partial)/(\partial x)(6ycos(x)) ?

The answer to (\partial)/(\partial x)(6ycos(x)) is -6ysin(x)

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(\partial)/(\partial x)(6ycos(x))

\frac{\partial}{\partial x} (6 y cos (x))

- 6 y sin (x)

Solution steps

\frac{\partial}{\partial x} (6 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 6 y (- sin (x))

Simplify

= - 6 y sin (x)

x \to 7 lim (\frac{1}{( x - 7 )})

\int sech^{2} (2 x - \frac{1}{8}) d x

\int \frac{1 + ln ( x )}{x} d x

\int ln (e^{6 x - 7}) d x

(2 - x)^{^{'}}

What is (\partial)/(\partial x)(6ycos(x)) ?
The answer to (\partial)/(\partial x)(6ycos(x)) is -6ysin(x)