What is the integral from-1 to 2 of x^3 ?

The integral from-1 to 2 of x^3 is 15/4

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integral from-1 to 2 of x^3

\int_{- 1}^{2} x^{3} d x

\frac{15}{4}

Decimal

3.75

Solution steps

\int_{- 1}^{2} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 1}^{2}

= [\frac{x ^{4}}{4}]_{- 1}^{2}

Compute the boundaries:

\frac{15}{4}

= \frac{15}{4}

x \to \infty lim (0. 6^{x})

f (x) = ln (x)

\frac{d}{d x} ((x + (x + sin^{2} (x))^{7})^{3})

\int t^{2} e^{- t^{3}} d t

x^{4}

What is the integral from-1 to 2 of x^3 ?
The integral from-1 to 2 of x^3 is 15/4