What is the derivative of 2x+cos(2x) ?

The derivative of 2x+cos(2x) is 2-sin(2x)*2

What is the first derivative of 2x+cos(2x) ?

The first derivative of 2x+cos(2x) is 2-sin(2x)*2

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\frac{d}{d x} (2 x + cos (2 x))

2 - sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 x + cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 - sin (2 x) \cdot 2

\int sin (\frac{nπ x}{L}) d x

f (t) = (t + 1)^{\frac{2}{3}} (2 t^{2} - 1)^{3}

\int \frac{1}{sec ( x ) tan ( x )} d x

\frac{d}{d t} (\frac{2 t + 5}{2 t})

\int x^{2} arctan (5 x) d x

What is the derivative of 2x+cos(2x) ?
The derivative of 2x+cos(2x) is 2-sin(2x)*2
What is the first derivative of 2x+cos(2x) ?
The first derivative of 2x+cos(2x) is 2-sin(2x)*2