What is the limit as t approaches 0 of ln(sin(4t)) ?

The limit as t approaches 0 of ln(sin(4t)) is Does not exist

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limit as t approaches 0 of ln(sin(4t))

t \to 0 lim (ln (sin (4 t)))

Does not exist

Solution steps

t \to 0 lim (ln (sin (4 t)))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 0 + lim (ln (sin (4 t))) = - \infty

t \to 0 - lim (ln (sin (4 t))) =

Does not exist

= Does not exist

\frac{\partial}{\partial x} (e^{\frac{2 x + 3 y}{3 y}})

\frac{d}{d x} (5 (e^{x})^{- 4})

x \to 2 lim (12 x^{2})

x \to - 2 lim (\frac{∣ x + 2 ∣}{x + 2})

\int \frac{sech ( \frac{1}{x} ) tanh ( \frac{1}{x} )}{x ^{2}} d x

What is the limit as t approaches 0 of ln(sin(4t)) ?
The limit as t approaches 0 of ln(sin(4t)) is Does not exist