What is the d/(dy)(e^{-x}+e^{-2y}) ?

The d/(dy)(e^{-x}+e^{-2y}) is -2e^{-2y}

What is the first d/(dy)(e^{-x}+e^{-2y}) ?

The first d/(dy)(e^{-x}+e^{-2y}) is -2e^{-2y}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d y} (e^{- x} + e^{- 2 y})

- 2 e^{- 2 y}

Solution steps

\frac{d}{d y} (e^{- x} + e^{- 2 y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (e^{- x}) + \frac{d}{d y} (e^{- 2 y})

\frac{d}{d y} (e^{- x}) = 0

\frac{d}{d y} (e^{- 2 y}) = - 2 e^{- 2 y}

= 0 - 2 e^{- 2 y}

Simplify

= - 2 e^{- 2 y}

f (x) = sin^{4} (x)

\frac{d}{d x} (100 x^{2})

y^{^{'}} = (x + y - 2) 2

\frac{\partial}{\partial x} (x ln (yz))

\int x e^{a x} d x

What is the d/(dy)(e^{-x}+e^{-2y}) ?
The d/(dy)(e^{-x}+e^{-2y}) is -2e^{-2y}
What is the first d/(dy)(e^{-x}+e^{-2y}) ?
The first d/(dy)(e^{-x}+e^{-2y}) is -2e^{-2y}