What is the integral of (2+x+x^2)/(sqrt(x)) ?

The integral of (2+x+x^2)/(sqrt(x)) is 4sqrt(x)+2/3 x^{3/2}+2/5 x^{5/2}+C

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integral of (2+x+x^2)/(sqrt(x))

\int \frac{2 + x + x ^{2}}{x} d x

4 x + \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{2 + x + x ^{2}}{x} d x

Expand

\frac{2 + x + x ^{2}}{x} : \frac{2}{x} + x + x^{\frac{3}{2}}

= \int \frac{2}{x} + x + x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x} d x + \int x d x + \int x^{\frac{3}{2}} d x

\int \frac{2}{x} d x = 4 x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

= 4 x + \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= 4 x + \frac{2}{3} x^{\frac{3}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

f (t) = \frac{sin ( t )}{t}

\int \frac{y}{e ^{- y}} d y

f (x) = \frac{x cos ( x ) - 2 π}{x - 2 π}

(\frac{m ^{2} + 2}{2 m ^{3} + 4})^{^{'}}

y^{^{''}} + 9 y = 4 cos (2 x)

What is the integral of (2+x+x^2)/(sqrt(x)) ?
The integral of (2+x+x^2)/(sqrt(x)) is 4sqrt(x)+2/3 x^{3/2}+2/5 x^{5/2}+C