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Popular >

derivative of 2+cos(e^x-2-e^x)

Solution

\frac{d}{d x} (2 + cos (e^{x} - 2) - e^{x})

Solution

- e^{x} - e^{x} sin (e^{x} - 2)

Solution steps

\frac{d}{d x} (2 + cos (e^{x} - 2) - e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (cos (e^{x} - 2)) - \frac{d}{d x} (e^{x})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (cos (e^{x} - 2)) = - sin (e^{x} - 2) e^{x}

\frac{d}{d x} (e^{x}) = e^{x}

= 0 - sin (e^{x} - 2) e^{x} - e^{x}

Simplify

= - e^{x} - e^{x} sin (e^{x} - 2)

Graph

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\int_{1}^{5} x^{4} ln (5 x) d x

tangent of y=x^{3-3x+1}tangent of

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\int 4 x - y^{2} d y

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\int_{1}^{3} \frac{1}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the derivative of 2+cos(e^x-2-e^x) ?
The derivative of 2+cos(e^x-2-e^x) is -e^x-e^xsin(e^x-2)
What is the first derivative of 2+cos(e^x-2-e^x) ?
The first derivative of 2+cos(e^x-2-e^x) is -e^x-e^xsin(e^x-2)