What is the d/(dt)(sin(3t)) ?

The d/(dt)(sin(3t)) is cos(3t)*3

What is the first d/(dt)(sin(3t)) ?

The first d/(dt)(sin(3t)) is cos(3t)*3

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\frac{d}{d t} (sin (3 t))

cos (3 t) \cdot 3

Solution steps

\frac{d}{d t} (sin (3 t))

Apply the chain rule:

cos (3 t) \frac{d}{d t} (3 t)

= cos (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= cos (3 t) \cdot 3

\frac{d}{d x} (y z (x))

\int 4 x^{3} + 2 x y^{2} d x

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{1}{3}})

4^{x}

\int_{0}^{4} x e^{- 3 x} d x