What is the derivative of f(x)=sqrt(2+x) ?

The derivative of f(x)=sqrt(2+x) is 1/(2sqrt(2+x))

What is the first derivative of f(x)=sqrt(2+x) ?

The first derivative of f(x)=sqrt(2+x) is 1/(2sqrt(2+x))

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derivative of

f (x) = 2 + x

\frac{1}{2 2 + x}

Solution steps

\frac{d}{d x} (2 + x)

Apply the chain rule:

\frac{1}{2 2 + x} \frac{d}{d x} (2 + x)

= \frac{1}{2 2 + x} \frac{d}{d x} (2 + x)

\frac{d}{d x} (2 + x) = 1

= \frac{1}{2 2 + x} \cdot 1

Simplify

= \frac{1}{2 2 + x}

x \to 2 lim (\frac{2 x - 3}{x - 2})

\frac{\partial}{\partial x} (e^{m x})

x sin (2 x)

\frac{8}{x}

\int e^{- 5 x^{2}} d x

What is the derivative of f(x)=sqrt(2+x) ?
The derivative of f(x)=sqrt(2+x) is 1/(2sqrt(2+x))
What is the first derivative of f(x)=sqrt(2+x) ?
The first derivative of f(x)=sqrt(2+x) is 1/(2sqrt(2+x))