What is the derivative of x^4-3x^2+3 ?

The derivative of x^4-3x^2+3 is 4x^3-6x

What is the first derivative of x^4-3x^2+3 ?

The first derivative of x^4-3x^2+3 is 4x^3-6x

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\frac{d}{d x} (x^{4} - 3 x^{2} + 3)

4 x^{3} - 6 x

Solution steps

\frac{d}{d x} (x^{4} - 3 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3) = 0

= 4 x^{3} - 6 x + 0

Simplify

= 4 x^{3} - 6 x

x \to 1 lim (\frac{∣ 3 - x ∣}{3 - x})

\frac{d}{d x} (\frac{x ^{2}}{5 + x})

e^{- t}

x \to 7 lim (9 x + ∣ x - 7 ∣)

y^{^{'}} - a y = 0

What is the derivative of x^4-3x^2+3 ?
The derivative of x^4-3x^2+3 is 4x^3-6x
What is the first derivative of x^4-3x^2+3 ?
The first derivative of x^4-3x^2+3 is 4x^3-6x