What is the tangent of f(x)=x^4+9x^2-x,(1,9) ?

The tangent of f(x)=x^4+9x^2-x,(1,9) is y=21x-12

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tangent of f(x)=x^4+9x^2-x,(1,9)

tangent of

f (x) = x^{4} + 9 x^{2} - x, (1, 9)

y = 21 x - 12

Solution steps

Find the slope of

f (x) = x^{4} + 9 x^{2} - x : \frac{df ( x )}{d x} = 4 x^{3} + 18 x - 1

Compute the slope of

f (x) = x^{4} + 9 x^{2} - x

(1, 9) : m = 21

Find the line with slope m=

21

and passing through

(1, 9) : y = 21 x - 12

y = 21 x - 12

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\frac{1}{( 8 ^{2} + 1 ) + ( 8 ^{2} + 4 )}

\int 2 e^{- 0.4 x} d x

\frac{d}{d x} (144 + x^{2})

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What is the tangent of f(x)=x^4+9x^2-x,(1,9) ?
The tangent of f(x)=x^4+9x^2-x,(1,9) is y=21x-12