What is the derivative of ln(1-9x) ?

The derivative of ln(1-9x) is -9/(1-9x)

What is the first derivative of ln(1-9x) ?

The first derivative of ln(1-9x) is -9/(1-9x)

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derivative of

ln (1 - 9 x)

- \frac{9}{1 - 9 x}

Solution steps

\frac{d}{d x} (ln (1 - 9 x))

Apply the chain rule:

\frac{1}{1 - 9 x} \frac{d}{d x} (1 - 9 x)

= \frac{1}{1 - 9 x} \frac{d}{d x} (1 - 9 x)

\frac{d}{d x} (1 - 9 x) = - 9

= \frac{1}{1 - 9 x} (- 9)

Simplify

\frac{1}{1 - 9 x} (- 9) : - \frac{9}{1 - 9 x}

= - \frac{9}{1 - 9 x}

x \to 1 lim (- \frac{3}{x - 1})

y^{^{'}} = y^{3} - 6 x^{2} y^{3}

\int e^{5 θ} sin (6 θ) d θ

1 0^{x}

\frac{d y}{d x} - 5 y = 6 e^{8 x}

What is the derivative of ln(1-9x) ?
The derivative of ln(1-9x) is -9/(1-9x)
What is the first derivative of ln(1-9x) ?
The first derivative of ln(1-9x) is -9/(1-9x)