What is the derivative of 1-sin(2x) ?

The derivative of 1-sin(2x) is -2cos(2x)

What is the first derivative of 1-sin(2x) ?

The first derivative of 1-sin(2x) is -2cos(2x)

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\frac{d}{d x} (1 - sin (2 x))

- 2 cos (2 x)

Solution steps

\frac{d}{d x} (1 - sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 0 - cos (2 x) \cdot 2

Simplify

= - 2 cos (2 x)

\frac{\partial}{\partial x} (z^{3} ln (y x))

2 \cdot ((t - 1)^{2}) \cdot 1 ((t - 1))

\frac{\partial}{\partial x} (\frac{7 x}{3 y})

f (x) = \frac{x}{2 x - 3}, (1, - 1)

\int \frac{e ^{- s t}}{s ^{2}} d t

What is the derivative of 1-sin(2x) ?
The derivative of 1-sin(2x) is -2cos(2x)
What is the first derivative of 1-sin(2x) ?
The first derivative of 1-sin(2x) is -2cos(2x)