What is the integral of (sqrt(u))/2 ?

The integral of (sqrt(u))/2 is 1/3 u^{3/2}+C

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integral of (sqrt(u))/2

\int \frac{u}{2} d u

\frac{1}{3} u^{\frac{3}{2}} + C

Solution steps

\int \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}} : \frac{1}{3} u^{\frac{3}{2}}

= \frac{1}{3} u^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} u^{\frac{3}{2}} + C

\frac{\partial}{\partial x} (x^{2} sin (y) cos (y))

\frac{d}{d v} (u^{2} - v^{2})

\int_{0}^{2} \frac{1}{x + 2} d x

x \to 0 lim (\frac{( cos ( 11 x ) - cos ( 6 x ) )}{x})

f (x) = x^{3} sin (x)

What is the integral of (sqrt(u))/2 ?
The integral of (sqrt(u))/2 is 1/3 u^{3/2}+C