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Popular >

ty^'=2

Solution

t y^{^{'}} = 2

Solution

y = 2 ln (t) + c_{1}

Solution steps

t y^{'} (t) = 2

Isolate

y^{'} (t) : y^{'} (t) = \frac{2}{t}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{2}{t} d t

\int \frac{2}{t} d t = 2 ln (t) + c_{1}

y = 2 ln (t) + c_{1}

Popular Examples

derivative of sec^2(sqrt(x))

\frac{d}{d x} (sec^{2} (x))

derivative of (sin(x)/(8xe^x))

\frac{d}{d x} (\frac{sin ( x )}{8 x e ^{x}})

\frac{d}{d t} (t^{5})

limit as x approaches 0 of tan(x)ln(x)

x \to 0 lim (tan (x) ln (x))

tangent of 1/(x^5)tangent of

\frac{1}{x ^{5}}

Frequently Asked Questions (FAQ)

What is the solution for ty^'=2 ?
The solution for ty^'=2 is y=2ln(t)+c_{1}