What is the solution for (d^2y)/(dx^2)+6(dy)/(dx)=0 ?

The solution for (d^2y)/(dx^2)+6(dy)/(dx)=0 is y=c_{1}+c_{2}e^{-6x}

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(d^2y)/(dx^2)+6(dy)/(dx)=0

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} = 0

y = c_{1} + c_{2} e^{- 6 x}

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 6 x}

y = c_{1} + c_{2} e^{- 6 x}

x \to - 3 lim (\frac{3 - ∣ x ∣}{3 + x})

y^{^{''}} + 6 y^{^{'}} + 34 y = 25 e^{- 3 x}

\frac{d}{d x} (4 x - 5 x^{\frac{5}{6}})

f (x) = x cos (x) + 2 tan (x)

\int coth (\frac{x}{3}) d x

What is the solution for (d^2y)/(dx^2)+6(dy)/(dx)=0 ?
The solution for (d^2y)/(dx^2)+6(dy)/(dx)=0 is y=c_{1}+c_{2}e^{-6x}