What is the sum from n=1 to infinity of (n+4)/(n^2) ?

The sum from n=1 to infinity of (n+4)/(n^2) is diverges

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sum from n=1 to infinity of (n+4)/(n^2)

n = 1 \sum \infty \frac{n + 4}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 4}{n ^{2}}

Apply Series Comparison Test:

diverges

= diverges

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\int 300 t e^{\frac{- t ^{2}}{7}} d t

What is the sum from n=1 to infinity of (n+4)/(n^2) ?
The sum from n=1 to infinity of (n+4)/(n^2) is diverges