What is the solution for (x^2-x)(dy)/(dx)=y-2xy ?

The solution for (x^2-x)(dy)/(dx)=y-2xy is y=(c_{1})/(x^2-x)

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(x^2-x)(dy)/(dx)=y-2xy

(x^{2} - x) \frac{d y}{d x} = y - 2 x y

y = \frac{c _{1}}{x ^{2} - x}

Solution steps

(x^{2} - x) \frac{d y}{d x} = y - 2 x y

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - x}

y = \frac{c _{1}}{x ^{2} - x}

\int_{0}^{2} 7 x^{3} x^{2} + 4 d x

\frac{d}{d x} (\frac{x ^{2} + 6 x}{10 - x ^{2}})

y^{^{''}} - 7 y^{^{'}} + 10 y = - sin (3 t)

y = x^{2} + 2 x - 11, y = 3, [3, 5]

\frac{\partial}{\partial x} (4 x sin (7 x^{2} y))

What is the solution for (x^2-x)(dy)/(dx)=y-2xy ?
The solution for (x^2-x)(dy)/(dx)=y-2xy is y=(c_{1})/(x^2-x)