What is the tangent of f(x)=-4/3 x^{-5/2},\at x=4 ?

The tangent of f(x)=-4/3 x^{-5/2},\at x=4 is y= 5/192 x-7/48

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=-4/3 x^{-5/2},\at x=4

tangent of

f (x) = - \frac{4}{3} x^{- \frac{5}{2}}, at x = 4

y = \frac{5}{192} x - \frac{7}{48}

Solution steps

Find the tangent point:

(4, - \frac{1}{24})

Find the slope of

f (x) = - \frac{4}{3} x^{- \frac{5}{2}} : \frac{df ( x )}{d x} = \frac{10}{3 x ^{\frac{7}{2}}}

Compute the slope of

f (x) = - \frac{4}{3} x^{- \frac{5}{2}}

x = 4 : m = \frac{5}{192}

Find the line with slope m=

\frac{5}{192}

and passing through

(4, - \frac{1}{24}) : y = \frac{5}{192} x - \frac{7}{48}

y = \frac{5}{192} x - \frac{7}{48}

\frac{d}{d x} (x (x - 1) (x - 2))

- 4 x^{2} + 9, x + 7

y^{^{'}} + 5 y = t e^{(4 t)}

\frac{\partial}{\partial x} (3 x^{2} - 4)

What is the tangent of f(x)=-4/3 x^{-5/2},\at x=4 ?
The tangent of f(x)=-4/3 x^{-5/2},\at x=4 is y= 5/192 x-7/48