What is area x=-2,x=1,y=e^x,y=3-e^x ?

The answer to area x=-2,x=1,y=e^x,y=3-e^x is 6ln(3/2)+2e+2/(e^2)-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x=-2,x=1,y=e^x,y=3-e^x

area

x = - 2, x = 1, y = e^{x}, y = 3 - e^{x}

6 ln (\frac{3}{2}) + 2 e + \frac{2}{e ^{2}} - 3

Decimal Notation

5.14002 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} ∣ e^{x} - (3 - e^{x}) ∣ d x

Solve

\int_{- 2}^{1} ∣ e^{x} - (3 - e^{x}) ∣ d x : 6 ln (\frac{3}{2}) + 2 e + \frac{2}{e ^{2}} - 3

The area is:

= 6 ln (\frac{3}{2}) + 2 e + \frac{2}{e ^{2}} - 3

\int (cot (x)) [ln (sin (x))] d x

\int x^{2} + x + 6 d x

\int \frac{3 x ^{2} + 5 x}{( x - 1 ) ( x + 1 ) ^{2}} d x

(x + 2 y^{2}) d x + x y d y = 0

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = x, y (1) = 0, y^{^{'}} (1) = 0

What is area x=-2,x=1,y=e^x,y=3-e^x ?
The answer to area x=-2,x=1,y=e^x,y=3-e^x is 6ln(3/2)+2e+2/(e^2)-3