What is the solution for (dy)/(dx)=((x^2+xy+y^2))/(x^2) ?

The solution for (dy)/(dx)=((x^2+xy+y^2))/(x^2) is y=tan(ln(x)+c_{1})x

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(dy)/(dx)=((x^2+xy+y^2))/(x^2)

\frac{d y}{d x} = \frac{( x ^{2} + x y + y ^{2} )}{x ^{2}}

y = tan (ln (x) + c_{1}) x

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} + x y + y ^{2} )}{x ^{2}}

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

h \to 0 lim (\frac{h ^{2}}{3 ∣ h ∣})

\int \frac{1}{sin ( x ) - 1} d x

\frac{d}{d x} (ln (4 x + 9))

x \to - 6 lim (\frac{x ^{2} - 5}{6 - x})

t y^{^{'}} + y = t^{2}

What is the solution for (dy)/(dx)=((x^2+xy+y^2))/(x^2) ?
The solution for (dy)/(dx)=((x^2+xy+y^2))/(x^2) is y=tan(ln(x)+c_{1})x