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Popular >

x^2y^'+y^2-xy=0

Solution

x^{2} y^{^{'}} + y^{2} - x y = 0

Solution

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) + y^{2} - x y = 0

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

Popular Examples

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\int (x + 1)^{10} (x + 2) d x

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\frac{1}{x - 6}

area x, 1/x , 1/2 area

x, \frac{1}{x}, \frac{1}{2}

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+y^2-xy=0 ?
The solution for x^2y^'+y^2-xy=0 is y= x/(ln(x)+c_{1)}