What is the integral of sqrt(x)(3x-2) ?

The integral of sqrt(x)(3x-2) is 6/5 x^{5/2}-4/3 x^{3/2}+C

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integral of sqrt(x)(3x-2)

\int x (3 x - 2) d x

\frac{6}{5} x^{\frac{5}{2}} - \frac{4}{3} x^{\frac{3}{2}} + C

Solution steps

\int x (3 x - 2) d x

Expand

x (3 x - 2) : 3 x^{\frac{3}{2}} - 2 x

= \int 3 x^{\frac{3}{2}} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{\frac{3}{2}} d x - \int 2 x d x

\int 3 x^{\frac{3}{2}} d x = \frac{6}{5} x^{\frac{5}{2}}

\int 2 x d x = \frac{4}{3} x^{\frac{3}{2}}

= \frac{6}{5} x^{\frac{5}{2}} - \frac{4}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{6}{5} x^{\frac{5}{2}} - \frac{4}{3} x^{\frac{3}{2}} + C

\frac{d y}{d x} + x y = y

\int_{- 1}^{9} 9 - x^{2} + 8 x d x

y^{^{'}} = \frac{5 x sec ( \frac{y}{x} ) + y}{x}

3 cos (t + \frac{π}{3})

What is the integral of sqrt(x)(3x-2) ?
The integral of sqrt(x)(3x-2) is 6/5 x^{5/2}-4/3 x^{3/2}+C