What is the sum from k=1 to infinity of (k!)/(2^k) ?

The sum from k=1 to infinity of (k!)/(2^k) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from k=1 to infinity of (k!)/(2^k)

k = 1 \sum \infty \frac{k !}{2 ^{k}}

diverges

Solution steps

k = 1 \sum \infty \frac{k !}{2 ^{k}}

Apply Series Ratio Test:

diverges

= diverges

\int_{- 1}^{1} x^{3} d x

\frac{d}{d x} (cos (5 12 - 4 x^{3}))

\int_{2}^{5} (x - 3)^{2} d x

\frac{\partial}{\partial z} (- 5 e^{x} cos (yz))

y = 3 x + 8 cos (x), (0, 8)

What is the sum from k=1 to infinity of (k!)/(2^k) ?
The sum from k=1 to infinity of (k!)/(2^k) is diverges