What is the first (sin(5x))^' ?

The first (sin(5x))^' is cos(5x)*5

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(sin(5x))^'

(sin (5 x))^{^{'}}

cos (5 x) \cdot 5

Solution steps

(sin (5 x))^{'}

Apply the chain rule:

cos (5 x) (5 x)^{'}

= cos (5 x) (5 x)^{'}

(5 x)^{'} = 5

= cos (5 x) \cdot 5

f (x) = x + \frac{1}{x}

n = 0 \sum \infty \frac{2}{3 ^{n}}

f (x) = (1 + x^{2}) (1 + x)

n \to \infty lim (\frac{e}{n})

x \to 1 lim ((2 x - 7)^{3})