What is the integral from 0 to infinity of 4xe^{-4x} ?

The integral from 0 to infinity of 4xe^{-4x} is 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of 4xe^{-4x}

\int_{0}^{\infty} 4 x e^{- 4 x} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{0}^{\infty} 4 x e^{- 4 x} d x

Compute the indefinite integral:

\int 4 x e^{- 4 x} d x = - e^{- 4 x} x - \frac{1}{4} e^{- 4 x} + C

Compute the boundaries:

\int_{0}^{\infty} 4 x e^{- 4 x} d x = 0 - (- \frac{1}{4})

= 0 - (- \frac{1}{4})

Simplify

= \frac{1}{4}

x y \cdot d x = (x^{2} + 4) d y

cos (sin (7 x))

h \to 0 lim (\frac{∣ h ∣}{h})

4 x

What is the integral from 0 to infinity of 4xe^{-4x} ?
The integral from 0 to infinity of 4xe^{-4x} is 1/4