What is (\partial)/(\partial x)(tan(2x+y)) ?

The answer to (\partial)/(\partial x)(tan(2x+y)) is sec^2(2x+y)*2

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(\partial)/(\partial x)(tan(2x+y))

\frac{\partial}{\partial x} (tan (2 x + y))

sec^{2} (2 x + y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (tan (2 x + y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (2 x + y) \frac{\partial}{\partial x} (2 x + y)

= sec^{2} (2 x + y) \frac{\partial}{\partial x} (2 x + y)

\frac{\partial}{\partial x} (2 x + y) = 2

= sec^{2} (2 x + y) \cdot 2

y = \frac{x - 6}{x + 6}

\frac{d}{d x} (\frac{8}{x ^{5}})

(0, 1), (5, - 2)

\int \frac{8 - x}{8 + x} d x

4 x + \frac{6}{7 x}

What is (\partial)/(\partial x)(tan(2x+y)) ?
The answer to (\partial)/(\partial x)(tan(2x+y)) is sec^2(2x+y)*2