What is the sum from n=1 to infinity of n/(1000n+1) ?

The sum from n=1 to infinity of n/(1000n+1) is diverges

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sum from n=1 to infinity of n/(1000n+1)

n = 1 \sum \infty \frac{n}{1000 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{1000 n + 1}

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (3^{x} x^{3})

\frac{d}{d x} (1 - x^{3})

\frac{d ^{4}}{d x ^{4}} (13 e^{x^{2}})

\frac{x ^{2} - 100}{x - 10}

f (x) = \frac{1}{2}

What is the sum from n=1 to infinity of n/(1000n+1) ?
The sum from n=1 to infinity of n/(1000n+1) is diverges