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Popular >

3y^{''}+12y=0

Solution

3 y^{^{''}} + 12 y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

3 y^{''} (t) + 12 y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Popular Examples

x(dy)/(dx)+3y=(1+x)/(x^3)

x \frac{d y}{d x} + 3 y = \frac{1 + x}{x ^{3}}

integral of 8/(1-cos(4x))

\int \frac{8}{1 - cos ( 4 x )} d x

integral of sin^2(4θ)

\int sin^{2} (4 θ) d θ

integral of (7x^2+3x+7)/((x^2+1)^2)

\int \frac{7 x ^{2} + 3 x + 7}{( x ^{2} + 1 ) ^{2}} d x

laplacetransform f(t)=5cos(8t)+3e^{-4}sin(3t)laplace transform

f (t) = 5 cos (8 t) + 3 e^{- 4} sin (3 t)

Frequently Asked Questions (FAQ)

What is the solution for 3y^{''}+12y=0 ?
The solution for 3y^{''}+12y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)