What is (\partial)/(\partial x)(ln(x)-1) ?

The answer to (\partial)/(\partial x)(ln(x)-1) is 1/x

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(\partial)/(\partial x)(ln(x)-1)

\frac{\partial}{\partial x} (ln (x) - 1)

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x)) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

\frac{\partial}{\partial x} (1) = 0

= \frac{1}{x} - 0

Simplify

= \frac{1}{x}

\int sec (x) - cos (x) d x

(4, - 7), (8, - 7)

f (x) = x ln (x) - x

\frac{1}{2} ln (x)

f (x) = \frac{1}{( x + 2 ) ^{2}}

What is (\partial)/(\partial x)(ln(x)-1) ?
The answer to (\partial)/(\partial x)(ln(x)-1) is 1/x