What is (\partial)/(\partial y)(3x^2y+y^2) ?

The answer to (\partial)/(\partial y)(3x^2y+y^2) is 3x^2+2y

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(\partial)/(\partial y)(3x^2y+y^2)

\frac{\partial}{\partial y} (3 x^{2} y + y^{2})

3 x^{2} + 2 y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (3 x^{2} y) = 3 x^{2}

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 3 x^{2} + 2 y

\frac{d}{d x} (ln ((5 x^{2} + 9)^{3}))

\int (sin (2 x) - cos (2 x))^{2} d x

4 x \frac{d y}{d x} + y = x^{3}

\frac{\partial}{\partial x} (e^{6 x e^{y}})

\frac{d y}{d t} = - 2 t y^{2}

What is (\partial)/(\partial y)(3x^2y+y^2) ?
The answer to (\partial)/(\partial y)(3x^2y+y^2) is 3x^2+2y