What is the derivative of (sqrt(3x)/4) ?

The derivative of (sqrt(3x)/4) is (sqrt(3))/(8sqrt(x))

What is the first derivative of (sqrt(3x)/4) ?

The first derivative of (sqrt(3x)/4) is (sqrt(3))/(8sqrt(x))

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\frac{d}{d x} (\frac{3 x}{4})

\frac{3}{8 x}

Solution steps

\frac{d}{d x} (\frac{3 x}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (3 x)

Apply the chain rule:

\frac{1}{2 3 x} \frac{d}{d x} (3 x)

= \frac{1}{2 3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= \frac{1}{4} \cdot \frac{1}{2 3 x} \cdot 3

Simplify

\frac{1}{4} \cdot \frac{1}{2 3 x} \cdot 3 : \frac{3}{8 x}

= \frac{3}{8 x}

\frac{7}{3 x ^{2}}

\frac{\partial}{\partial x} (sin^{3} (2 x))

h (t) = (7 t^{2} + t)^{- 3}

y^{^{'}} = 2 y + x^{2} + 5

\int_{0}^{π} 3 x sin (x) d x

What is the derivative of (sqrt(3x)/4) ?
The derivative of (sqrt(3x)/4) is (sqrt(3))/(8sqrt(x))
What is the first derivative of (sqrt(3x)/4) ?
The first derivative of (sqrt(3x)/4) is (sqrt(3))/(8sqrt(x))