What is (\partial)/(\partial y)(6xy^2) ?

The answer to (\partial)/(\partial y)(6xy^2) is 12xy

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(\partial)/(\partial y)(6xy^2)

\frac{\partial}{\partial y} (6 x y^{2})

12 x y

Solution steps

\frac{\partial}{\partial y} (6 x y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 x \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 x \cdot 2 y^{2 - 1}

Simplify

= 12 x y

\int 4 x ln (7 x) d x

\frac{\partial}{\partial x} (ln (2 x + y + 1))

y^{^{'}} + 3 y = 8 x, y (0) = 4

f (x) = 1 - 9 x^{2}, at x = 3

n = 0 \sum \infty (- \frac{5}{4})^{n}

What is (\partial)/(\partial y)(6xy^2) ?
The answer to (\partial)/(\partial y)(6xy^2) is 12xy